Question

hey pls answer explain
3x^2+4x+3=0​

Answer 1

Answer:

$\Large{\underline{\bf{Solution}}}}$

$\red\bold{GIVEN,}}}}$

$\Large\purple{\underline{\bf{The quadratic Formula}}}}$

$x = \frac{-b ± √b^{2} - 4ac}{2a}$

$\fbox{SOLVE}$

$ax^{2} + bc + c = 0$

$\red\bold{\underline{\underline{Since}}}}$

a ⟹ 3

b ⟹ 4

c ⟹ -3

We have,

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

$x ⟹ \frac{-4 ± √4^{2}-4.3.(-3)}{2.3}$

$⟹\frac{-4±√16+36}{6}$

$⟹\frac{-4 ±√52}{6}$

$⟹\frac{-4 ± 4√13}{6}$

[tex] ⟹\frac{-2 ± 2√13}{3}[\tex]

Answer 2

Step-by-step explanation:

${3x}^{2} + 4x + 3 = 0 \\ \\ \: according \: to \: the \: formula \\ {ax}^{2}bx + c \\ a = 3 \\ b = 4 \\ c = 3$

$putting \: the \: value \: \\ {4}^{2} - 4 \times 3 \times 3 \\ 16 - 36 \\ - 20$

According to the FORMULA :-

${b}^{2} - 4ac = 0$