hey pls answer the question
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Answer:
Step-by-step explanation:
∠acd=∠bac
∠ABC=70
IN TRIANGLE ΔABC
∠ACD=∠A+∠B -----------(2)----------(SUM OF TWO INTERIOR ∠ = EQUAL TO EXTERIOR ∠ )
PUTTING THE VALUE OF ∠ACD IN FOLLOWING EQUATION
WE GET
2∠A=∠A+∠B
∠A-2∠A=70°
∠A=70
A/Q
2∠BAC=∠ACD
2*70=∠ACD
∠ACD=140°
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