hey pls answer this question .
very urgent..!!
first and correct answer to be marked as brainliest.
Answers
Answer:
4 hours 40 minutes
Step-by-step explanation:
Let the two taps be A and B.
(i) Tap A can fill the tank in 10 hours.
Amount of tank filled in 1-hour = (1/10).
(ii) Tap B can fill the tank in 5 hours.
Amount of tank filled in 1 -hour = (1/5).
Work done by (A + B) in 1-hour = (1/10) + (1/5)
= 3/10.
Now,
Given that first tap is opened and allowed to run for 2 hours.
Tap A in 1-hour = (1/10).
Tap B in 2-hours = (2/10) = 1/5.
Amount of work left = 1 - (1/5) = 4/5.
So,
The time taken by both the taps to fill (4/5) part = (10/3) * (4/5)
= 40/15
= 8/3 hours
But, it is given that It is allowed to run for 2 hours.
= 2 + (8/3)
= 14/3 hours
= (14/3) * 60
= 280 minutes
= 4 hours 40 minutes.
Hope it helps!
(i) Tap A can fill the tank in 10 hours.
Amount of tank filled in 1-hour = (1/10).
(ii) Tap B can fill the tank in 5 hours.
Amount of tank filled in 1 -hour = (1/5).
Work done by (A + B) in 1-hour = (1/10) + (1/5)
= 3/10.
Now,
Given that first tap is opened and allowed to run for 2 hours.
Tap A in 1-hour = (1/10).
Tap B in 2-hours = (2/10) = 1/5.
Amount of work left = 1 - (1/5) = 4/5.
So,
The time taken by both the taps to fill (4/5) part = (10/3) * (4/5)
= 40/15
= 8/3 hours
But, it is given that It is allowed to run for 2 hours.
= 2 + (8/3)
= 14/3 hours
= (14/3) * 60
= 280 minutes
= 4 hours 40 minutes.