Question

Heý plzź answer it fast..!!!

Answer 1

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Answer 2

Howdy!!!

your answer is ----

Given,
${x}^{2} + \frac{1}{ {x}^{2} } = 27$

now,

${(x + \frac{1}{x}) }^{2} = {x}^{2} + \frac{1}{ {x}^{2} } + 2 \\ = 27 + 2 = 29 \\ = > x + \frac{1}{x } = \sqrt{29}$


now,
${(x - \frac{1}{x} )}^{2} = {x}^{2} + \frac{1}{ {x}^{2} } - 2 \\ = 27 - 2 = 25 \\ = > x - \frac{1}{x} = \sqrt{25} = 5$

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