Question

Hey. Plz answer this question

Answer 1

Formula

Area of Δ = 1/2 × base of Δ × height of Δ

Approach

Area of ABCD = Area of Δ ABC + Area of Δ ACD

Area of Δ ABC

Area = 1/2 × b × h

        = 1/2 × AC × BM

        = 1/2 × 22 cm × 3 cm

        = 11 cm × 3 cm

        = 33 cm²

Area of Δ ACD

Area = 1/2 × b × h

        = 1/2 × AC × DN

        = 1/2 × 22 cm × 3 cm

        = 11 cm × 3 cm

        = 33 cm²

Area of ABCD

Area = Area of Δ ABC + Area of Δ ACD

        =  33 cm² + 33 cm²

        = 66 cm²

$\mathfrak{\underline{\underline{ANSWER}}}$

Area of ABCD is 66 cm².