hey....
plz do 4th question for me... urgent
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p(y) =3y^2-2y+8
y =2
p(2) =3×(2)^2-2(2)+8
=(3×4)-4+8
=12-4+8
=8+8
=16
Thus,
p(y) =3y^2-2y+8 is equal to 16 when y=2....
Hope it will help u....
y =2
p(2) =3×(2)^2-2(2)+8
=(3×4)-4+8
=12-4+8
=8+8
=16
Thus,
p(y) =3y^2-2y+8 is equal to 16 when y=2....
Hope it will help u....
Khushi111111111111:
Thanks for marking me brainliest
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