Question

Hey plz do ques no 20 and 21

Answer 1

$\bold{Answer :}$

$\bold{(20)}$

The paths, already walked by them are 24 m, 30 m and 36 m

We need to find the LCM of 24, 30 and 36 in order to find the required distance at which they meet.

Now,

24 = 2 × 2 × 2 × 3

30 = 2 × 3 × 5

36 = 2 × 2 × 3 × 3

So, LCM (24, 30, 36)

= 2 × 2 × 2 × 3 × 3 × 5

= 360

Hence, after 270 m of run by each, they will meet.

$\bold{(21)}$

The two sections having students 24 and 36 for each.

Now, to find the maximum number of students to be in each row, we need to find the HCF of 24 and 36

Now,

24 = 2 × 2 × 2 × 3

36 = 2 × 2 × 3 × 3

So, HCF (24, 36)

= 2 × 2 × 3

= 12

Hence, each row can have 12 students.

#$\bold{MarkAsBrainliest}$