hey plz give me ans
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Answered by
4
Answer:
1)
2
x
2
+
4
x
+
6
=
2
(
x
2
+
2
x
+
3
)
The expression
x
2
+
2
x
+
3
is of the form
a
x
2
+
b
x
+
c
, with
a
=
1
,
b
=
2
and
c
=
3
This has discriminant given by the formula:
Δ
=
b
2
−
4
a
c
=
2
2
−
(
4
×
1
×
3
)
=
4
−
12
=
−
8
Since
Δ
<
0
the equation
x
2
+
2
x
+
3
=
0
has no real roots,
so there are no linear factors with real coefficients.
2)Given : 7(x−2y)
2
−25(x−2y)+12
Let us consider x−2y=z
So we get,
=7z
2
−25z+12
We can further write it as
=7z
2
−21z−4z+12
By taking out the common terms
=7z(z−3)−4(z−3)
=(7z−4)(z−3)
Let us replace z by x−2y
So we get
7(x−2y)
2
−25(x−2y)+12
Then,
=(7(x−2y)−4)((x−2y)−3)
=(7x−14y−4)(x−2y−3)
7(x−2y)
2
−25(x−2y)+12=(2a−b+1)(18a−9b−13)
Step-by-step explanation:
hope it was helpful.....
Answered by
1
Answer:
=×^2+8x+12=0
x^2+6x+2x+12
x(x+6)+2(x+6)
(x+6)(x+2)
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