Question

hey plz give me ans ​

Answer 1

Answer:

1)

2

x

2

+

4

x

+

6

=

2

(

x

2

+

2

x

+

3

)

The expression

x

2

+

2

x

+

3

is of the form

a

x

2

+

b

x

+

c

, with

a

=

1

,

b

=

2

and

c

=

3

This has discriminant given by the formula:

Δ

=

b

2

−

4

a

c

=

2

2

−

(

4

×

1

×

3

)

=

4

−

12

=

−

8

Since

Δ

<

0

the equation

x

2

+

2

x

+

3

=

0

has no real roots,

so there are no linear factors with real coefficients.

2)Given : 7(x−2y)

2

−25(x−2y)+12

Let us consider x−2y=z

So we get,

=7z

2

−25z+12

We can further write it as

=7z

2

−21z−4z+12

By taking out the common terms

=7z(z−3)−4(z−3)

=(7z−4)(z−3)

Let us replace z by x−2y

So we get

7(x−2y)

2

−25(x−2y)+12

Then,

=(7(x−2y)−4)((x−2y)−3)

=(7x−14y−4)(x−2y−3)

7(x−2y)

2

−25(x−2y)+12=(2a−b+1)(18a−9b−13)

Step-by-step explanation:

hope it was helpful.....

Answer 2

Answer:

=×^2+8x+12=0

x^2+6x+2x+12

x(x+6)+2(x+6)

(x+6)(x+2)