Math, asked by Anonymous, 10 months ago

hey plz help the kid in that que​

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Answered by Mysterioushine
1

 \sqrt{3}  \:  \: tan2x \:  = sin30 + sin45.cos45 + 2sin90 \\  \\  =  >  \sqrt{3}  \:  \: tan2x =  \frac{1}{2}  +  \frac{1}{ \sqrt{2} } . \frac{1}{ \sqrt{2} }  + 2 \times 1 \\  \\  =  >  \sqrt{3}  \:  \: tan2x = 1 + 2 = 3 \\  \\  =  >    \:  \: tan2x =  \frac{3}{ \sqrt{3} }  =  \frac{3 \sqrt{3} }{3}  =  \sqrt{3}  \\  \\  =  > tan2x = tan60 \\  \\  =  > 2x = 60 =  > x = 30

Answered by ayush3520
3

did you watched anything other than tokyo Ghoul yet?

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