hey plz solve it....
Attachments:

Answers
Answered by
1
May this will help you......
Attachments:

Answered by
1
1.tan 80 tan10 tan15 tan75
tan (90-10) tan10. tan (90-75) tan75
tan10 tan10 . tan75 tan 75. ( by canceling)
= 1
2.sin 26°/ cosec ( 90- 26) +. cos( 90-64)/ cosec 64°
sin26/sec 26 +. cos64/ cosec 64.
now u can solve
tan (90-10) tan10. tan (90-75) tan75
tan10 tan10 . tan75 tan 75. ( by canceling)
= 1
2.sin 26°/ cosec ( 90- 26) +. cos( 90-64)/ cosec 64°
sin26/sec 26 +. cos64/ cosec 64.
now u can solve
Similar questions
India Languages,
9 months ago
English,
9 months ago
Biology,
9 months ago
Political Science,
1 year ago
Chemistry,
1 year ago
English,
1 year ago