Question

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Answer 1

Answer:

Step-by-step explanation:

hey

first rationalise the denominator

(3 root 2-2 root 3)/(3 root 2 + 2 root 3)*(3 root 2-2 root 3)/(3 root 2-2 root 3)

=(3 root 2-2 root 3)^2/(3 root 2^2-2 root 3^2)

=18+12-6 root 6/6

6(5- root 6)/6

=5-root 6

Answer 2

⏪⏪ HEY ⏩⏩

YOUR SOLUTION ⤵⤵⤵

On rationalising denominator

=> $\frac{3 \sqrt{2} - \: 2 \sqrt{3} }{3 \sqrt{2 \: } + 2 \sqrt{3}} \times \frac{3 \sqrt{2} - 2 \sqrt{3} }{3 \sqrt{2 \: } - 2 \sqrt{3} }$

=> $\frac{ ({3 \sqrt{2 } - 2 \sqrt{3} )}^{2} }{({3 \sqrt{2})}^{2} - {(2 \sqrt{3} )}^{2} }$

=> $\frac{30 - 12 \sqrt{6} }{18 - 12}$

=> $\frac{6(5 - 2 \sqrt{6} )}{6} = 5 - 2 \sqrt{6}$

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