Physics, asked by smitpandhare43pbe9lt, 1 year ago

Hey....Plzz answer que. 61...




Solution needed....

Attachments:

meenakshi997sa: 3rd option is wrong... because the trigonometric ratio must be dimensionless but here it is not

Answers

Answered by Anonymous
2
Dimensions:
 
t :  time  = T
Time period = T
velocity :  L / T
 a = displacement = L
 y = displacement = L

a)  L = L Sin L/L          this is okay...

b)   L = L sin  L/T * T  = L Sin L    ... this is not alright, as L is not radians.. Argument of Sine function should be in radians and dimensionless.

c)  L = L/T  Sin T/L        not correct

d)   L = L  (Sin  T/T  + Cos  T/T)          this is alright...



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