hey, plzz answer these questions.... ☺️
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sanjay270899:
Number 29 bhi solve karna hai?
plzz solve 29th also..
Your both ticked answers are right.
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>>>28.
Surjective means range = co-domain.
Now lets find the range of f(x).
A = {2,3,4}
f(2) = 4
f(3) = 4.5
f(4) = 5.33
Range = {4, 4.5, 5.33 }
So, B = {4, 4.5, 5.33 }
Thus, n(B) = 3
>>>29.
f(x) = 8^(1+lnx) / x^(ln8)
f(x) = 8^(1+lnx) / 8^(lnx)
f(x) = 8^(1+lnx-lnx)
f(x) = 8^1
f(x) = 8
which is independent of x.
Surjective means range = co-domain.
Now lets find the range of f(x).
A = {2,3,4}
f(2) = 4
f(3) = 4.5
f(4) = 5.33
Range = {4, 4.5, 5.33 }
So, B = {4, 4.5, 5.33 }
Thus, n(B) = 3
>>>29.
f(x) = 8^(1+lnx) / x^(ln8)
f(x) = 8^(1+lnx) / 8^(lnx)
f(x) = 8^(1+lnx-lnx)
f(x) = 8^1
f(x) = 8
which is independent of x.
And, are my answers correct??
What is written after log in question? Picture is not clear somewhat...
[(8) power (1+log x to the base e)] ÷ [(x) power (log 8 to the base e)]
Answer of 28. (3) and Answer of 29. (8).
Answer Edited. :)
thanks..
If any other answers the question, then I will mark u as brainliest...
but anyways thank you so much...
Welcome. Credit for the second answer goes to my brother.
oh..
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0
Answer:
aese questions mujhse nahi bante hai,
mujhe lagta hai aap maths me bahot intelligent ho.
Good keep it up .
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