Hey plzz solve question no 23
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Each angle of hexagon = 120°
Area of a sector = theta/360° * πr^2
= 120°/360° * πr^2
= πr^2 / 3
Area of six such sectors = 6 (πr^2 / 3)
= 2πr^2
Hope this helps!!!
Plsss make it the brainiest!!!
Area of a sector = theta/360° * πr^2
= 120°/360° * πr^2
= πr^2 / 3
Area of six such sectors = 6 (πr^2 / 3)
= 2πr^2
Hope this helps!!!
Plsss make it the brainiest!!!
akshatrock111:
It's correct
thanks
thnx
to u buddy
thnx a lottt for making it the brainliest answer....
wlcm
Answered by
1
Ok it will help you out
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