Question

Hey! Prove the equation asked! Thanks! ​

Answer 1

Refer the attached picture.

$\rm\underline {\large{Identity \:Used}}$ :

$sin {}^{2} \alpha \: + cos {}^{2} \alpha = 1$

$\frac{1}{sin\: a }$ = cosec a [ Or vice - versa ]

$\frac{1}{cos\: a }$ = sec a [ Or vice - versa ]

$( \: a + b \: ) {}^{2} = a {}^{2} + b {}^{2} + 2ab$