Math, asked by duragpalsingh, 1 year ago

Hey!

Question for Brilliant Math Experts.

(Attachment Enclosed)

Good luck!

Attachments:

Answers

Answered by mysticd
8
Hi ,

| x - 5 | < -1

| x - 5 | never be negative

positive number < -1 is not

possible .

option K is correct ,

I hope this helps you.

:)
Answered by abhi178
6
it's based on Modulus concept .
Let's start to break Modulus .

|x - 5 | < -1

case 1 : when x ≥ 5
then, ( x - 5) > 0 hence, mode break with positive sign .
e.g (x - 5) < -1
x - 5 + 1 < 0
x - 4 < 0 => x < 4
now,
there is no any set which is common in x > 5 and x < 4
hence, x∈ Φ


case 2 : - when x < 5
then, (x - 5) < 0, hence mode break with negative sign .
e.g., -(x - 5) < -1
-x + 5 < -1
-x + 5 + 1 < 0
-x + 6 < 0 => x > 6
now, take common in x < 5 and x > 6 ,
we get , x ∈ Φ

hence, there are no any set in which
|x - 5 | < -1
so, Option K is correct .

you can understand it with graph too .
see attached graph ,
above graph doesn't intersects or overlaps the below graph .
hence, x ∈ Φ
Attachments:
Similar questions