Hey say to me answer.
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hey buddy here is ur ans
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I.135 and 225
since 135<225
we will apply division algorithm
225=135*1+90
since 90 is not equal to 0
again we will do the same
135=90*1+45
since 45 is not eq. to 0
same method will be applied
90=45*2+0
SO AS WE GOT 0 NOW THEN THE DIVISOR I.E.45 IS HCF OF 135 AND 225
II.196 and 38220
since 38220>196
we will apply division algorithm
32880=196*195+0
SO AS WE GOT 0 NOW THEN THE DIVISOR I.E.196 IS HCF OF 38220 AND 196
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hope it helps plzz mark brainliest
.
.
.
.
.
I.135 and 225
since 135<225
we will apply division algorithm
225=135*1+90
since 90 is not equal to 0
again we will do the same
135=90*1+45
since 45 is not eq. to 0
same method will be applied
90=45*2+0
SO AS WE GOT 0 NOW THEN THE DIVISOR I.E.45 IS HCF OF 135 AND 225
II.196 and 38220
since 38220>196
we will apply division algorithm
32880=196*195+0
SO AS WE GOT 0 NOW THEN THE DIVISOR I.E.196 IS HCF OF 38220 AND 196
.
.
.
hope it helps plzz mark brainliest
Answered by
1
Hey mate...
here is your answer
I hope it will help you
here is your answer
I hope it will help you
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