hey scooter moving at a speed of 10 M per second is stopped by applying brakes without producing a uniform acceleration of minus 0.5 m per second square how much distance will be covered by scooter before it stops
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initial velocity of scooter=10 m/sfinal velocity......................=0 m/sacceleration of ..............=-0.5 m/s²apply formula v²-u²=2as-100=2x-0.5xs-100=-ss=100distance traveled by scooter before it stops is 100m
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no he was doing before u i have seen
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u-10m/s
v-0
acc.- -0.5m/s2
dis.cov-?
applying third eq. of motion
v2-u2plus2as
(0)2-(10)2plus2multi.-0.5multi.s
0-100-s
s-100m
dis-100m
'-'means equal to
v-0
acc.- -0.5m/s2
dis.cov-?
applying third eq. of motion
v2-u2plus2as
(0)2-(10)2plus2multi.-0.5multi.s
0-100-s
s-100m
dis-100m
'-'means equal to
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