Hey smarties
Pls help me cuz I have my maths exam tomorrow so pls help me
Mohan Lal left one-third of his property to his daughter, one-fourth to his son and the remainder to his wife. If the wife’s share was worth Rs.40,000 how much money did Mohan Lal have?
Thnx in advance
Answers
Answered by
1
Step-by-step explanation:
let the money mohan Lal have = Rs x
daughter's share= x/3.
son's share = x/4
wife's share in money = Rs. 40,000
A/Q
x -(x/3 + x/4)= 40,000
x- ( 4x + 3x)/12 = 40,000
x- 7x/12 =40000
5x/12 =40000
cancel 40,000 by 5 then we get 8000
now,
x= 12×8000
= 96000
hence,
Mohan lal have 96000 rupees.
hope it helps you.
Answered by
2
Answer:
let the money mohan Lal have = Rs x
daughter's share= x/3.
son's share = x/4
wife's share in money = Rs. 40,000
A/Q
x -(x/3 + x/4)= 40,000
x- ( 4x + 3x)/12 = 40,000
x- 7x/12 =40000
5x/12 =40000
cancel 40,000 by 5 then we get 8000
now,
x= 12×8000
= 96000
hence,
Mohan lal have 96000 rupees.
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