Math, asked by xfaizahassanchyx, 2 months ago

Hey smarties
Pls help me cuz I have my maths exam tomorrow so pls help me
Mohan Lal left one-third of his property to his daughter, one-fourth to his son and the remainder to his wife. If the wife’s share was worth Rs.40,000 how much money did Mohan Lal have?
Thnx in advance

Answers

Answered by mdsaquibmth
1

Step-by-step explanation:

let the money mohan Lal have = Rs x

daughter's share= x/3.

son's share = x/4

wife's share in money = Rs. 40,000

A/Q

x -(x/3 + x/4)= 40,000

x- ( 4x + 3x)/12 = 40,000

x- 7x/12 =40000

5x/12 =40000

cancel 40,000 by 5 then we get 8000

now,

x= 12×8000

= 96000

hence,

Mohan lal have 96000 rupees.

hope it helps you.

Answered by Najibm5441
2

Answer:

let the money mohan Lal have = Rs x

daughter's share= x/3.

son's share = x/4

wife's share in money = Rs. 40,000

A/Q

x -(x/3 + x/4)= 40,000

x- ( 4x + 3x)/12 = 40,000

x- 7x/12 =40000

5x/12 =40000

cancel 40,000 by 5 then we get 8000

now,

x= 12×8000

= 96000

hence,

Mohan lal have 96000 rupees.

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