Question

Hey !!!

solve these questions :-D

Answer 1

HELLO !!!!.......


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(9)
==>
●Given, 0.1 mole of Cu2+ is present,
So, Charge on cupric ion = 2+
Also, Charge of electron = 1.602 x 10-19 C

●Number of cupric ions present in 0.1 mole = 0.1 x avogadro number

  = 0.1 x 6.02 x 1023 particles
   = 6.02 x 1022

●As charge on cupric ion is 2+ ,

●Charge on the two electrons, 2 x 1.602 x 10-19= 3.204 x 10-19C

●Therefore, charge on 6.02 x 1022 particles = 3.204 x 10-19 x 6.02 x 1022

   = 1.9288 x 104 C


==> So, the charge present in 0.1 mole of Cu2+ ions is 1.9288 x 104 C.



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(10)

==> 10 lakh = 100,000 x 10 = 1,000,000 rupees per second

So, to spend Avogadro Number of rupees at the rate of one million per second requires this:

6.022 x 1023 rupee divided by 1 x 106rupee/sec = 6.022 x 1017 seconds

(365 da/yr) x (24 hr/da) x (3600 sec/hr) = 31536000 sec/yr

Thus there are 31536000 sec in a year

No. of years it would take to spend avagadro no. of rupees at the rate of 10 lakh rupees per second = 

6.022 x 1017 seconds/ 31536000 sec/yr

= 1.9 x 1010 years.

The answer is 1.9 x 1010 years. That's a rather long time!

$(19.08 \times {10}^{9} )$


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Answer 2

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