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1x/3 + y = 10 ---- (1)
Taking the LCM of the denominators and then solving it.
⇒ x + 3y = 30.
2x + 1y/4 = 11/4 ----- (2)
(3) Taking the LCM of the denominators and the solving it.
⇒ 8x + y = 11
(4) Multiplying the equation (4) by 3, we get
→ (8x + y = 11)*3
= 24x + 3y = 33
Now subtracting it from equation---- (2)
x + 3y = 30 24x + 3y = 33
- 23x = -3
⇒ 23x = 3
x = 3/23
Now, substituting the value of x = = 3/23 in
(2).⇒ x + 3y = 30
→ 3/23 + 3y = 30
→ 3y = 30 - 3/23
3y = (690-3)/23
Зу = 687/23
⇒ y = 687/23*3
⇒ y = 687/69
⇒ y = 229/23
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