Question

Hey!

Solve this
$\frac{2x + 1}{3x - 2} = \frac{9}{1 0}$


Fast please
Do in copy please ​

Answer 1

GIVEN :

$\frac{2x + 1}{3x - 2} = \frac{9}{1 0}$

We should cross Multiply the above terms.

Then,

10(2x + 1) = 9(3x - 2)

20x + 10 = 27x - 18

Transport 10 to RHS and 27x to LHS

20x - 27x = -18 - 10

-7x = -28

7x = 28

x = 28/7

x = 4

VERIFICATION :

$\frac{2x + 1}{3x - 2} = \frac{9}{1 0}$

Substitute value of x in the place of x

$\frac{2(4) + 1}{3(4) - 2} = \frac{9}{1 0}$

$\frac{8 + 1}{12 - 2} = \frac{9}{1 0}$

$\frac{9}{10} = \frac{9}{1 0}$

Therefore, the value of x is 4.