Question

hey ......
some one plzzzzzzz explain me..... how do we calculate this...... !!!! do explain it properly...... and just don't copy and paste............

plzz it's urgent......!!....!!...

Answer 1

Bonjour!

According to the question;

200 ml of N/10 H2SO4 is mixed into 300 ml N/100 NaOH.

Formula to solve this question:-

NV = N1V1 - N2V2

N1 = 1/10

V1 = 200

N2 = 1/100

V2 = 300

V = 500

N = ?


$= > N \times 500 = \frac{1}{10} \times 200 - \frac{1}{100} \times 300 \\ \\ = > N \times 500 = 17 \\ \\ = > N = \frac{17}{500} \\ \\ = > N = 0.034$

So, the Normality of the resulting solution is 0.034 N

Hope this helps...:)