Hey someone please write in a paper and send .....
factorise 4x² + 9y² + 16z² + 12xy - 24yz - 16z.
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A small correction is needed. It should be 16xz.
Now,
Given Equation is 4x^2 + 9y^2 + 16z^2 + 12xy - 24yz - 16xz
It can be written as,
= > (2x)^2 + (3y)^2 + (4z)^2 + (2)(2)(3)xy + 2(3y)(-4z) + 2(2x)(-4z)
It is in the form of a^2 + b^2 + c^2 + 2ab + 2bc + 2ca = (a + b + c)^2
Here a = 2x, b = 3y, c = 4z.
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Therefore The result is (2x + 3y - 4z)^2 (or) (2x + 3y - 4z)(2x + 3y - 4z).
Hope this helps!
misshshareef07pdij86:
Sis what does this mean ^ ?
and thanks yew somch fr the correction
power. For example 2^2 = 2 is called as 2 to the power 2 = 4.
Aha thank yew once again
what if someone write power of 3 ? It will b same as ^?
yes... 3 to the power can be written as 3^3.
Aha thnx
Its ok..sorry i dont have paper with me at present. i was trying to sleep!
Aha woow ... thank yew somch ....
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