Question

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Answer 1

Given a + b + c = 0 and a^2 + b^2 + c^2 = 16.

We know that (a + b + c)^2 = (a^2 + b^2 + c^2) + 2(ab + bc + ca)

= > 0 = 16 + 2(ab + bc + ca)

= > -16 = 2(ab + bc + ca)

= > -8 = ab + bc + ca


Hope this helps!

Answer 2

ans is -8
given = a+b+c = 0
a^2+b^2+c^2 = 16
then,
by applying formula
(a+b+c)^2 = a^2+b^2+c^2+2(ab+bc+ca)
we get,
(0)^2= 16+2(ab+bc+ca)
(ab+bc+ca) = -16/2
                   =-8                                                                          Answer...