HEY THERE BUDDIES....how to deal with this......(a-2b+5c)(a-b)-(a-b-c)(2a+3c)+(6a+b)(2c-3a-5b)
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Hi ,
1 ) ( a - 2b + 5c ) ( a - b )
= a ( a - b )-2b(a -b ) +5c ( a - b )
= a² - ab - 2ab + 2b² + 5ac - 5bc
= a² + 2b² -3ab - 5bc + 5ac ---( 1 )
2 ) ( a - b - c ) ( 2a + 3c )
= a(2a + 3c ) - b ( 2a + 3c ) - c( 2a+ 3c )
= 2a² + 3ac - 2ab - 3bc - 2ac - 3c²
= 2a² - 3c² - 2ab - 3bc + ac ---( 2 )
3 ) ( 6a+ b ) ( 2c - 3a - 5b )
= 6a( 2c - 3a - 5b ) + b (2c - 3a - 5b )
= 12ac - 18a² - 30ab + 2bc - 3ab - 5b²
= - 18a² - 5b² - 33ab + 2bc +12ac--( 3 )
Now ,
According to the problem given ,
( 1 ) - ( 2 ) + ( 3 )
= a² + 2b² - 3ab - 5bc + 5ac
- ( 2a² - 3c² - 2ab - 3bc + ac )
+ ( -18a² - 5b² - 33ab + 2bc + 12ac)
= ( 1 - 2 - 18 ) a² + ( 2 - 5 )b² + 3c²
+ ( -3 + 2 - 33 ) ab + (-5 + 3 + 2 ) bc
+ ( 5 - 1 + 12 ) ac
= -19a² - 3b² + 3c² - 34ab + 16ac
I hope this helps you.
: )
1 ) ( a - 2b + 5c ) ( a - b )
= a ( a - b )-2b(a -b ) +5c ( a - b )
= a² - ab - 2ab + 2b² + 5ac - 5bc
= a² + 2b² -3ab - 5bc + 5ac ---( 1 )
2 ) ( a - b - c ) ( 2a + 3c )
= a(2a + 3c ) - b ( 2a + 3c ) - c( 2a+ 3c )
= 2a² + 3ac - 2ab - 3bc - 2ac - 3c²
= 2a² - 3c² - 2ab - 3bc + ac ---( 2 )
3 ) ( 6a+ b ) ( 2c - 3a - 5b )
= 6a( 2c - 3a - 5b ) + b (2c - 3a - 5b )
= 12ac - 18a² - 30ab + 2bc - 3ab - 5b²
= - 18a² - 5b² - 33ab + 2bc +12ac--( 3 )
Now ,
According to the problem given ,
( 1 ) - ( 2 ) + ( 3 )
= a² + 2b² - 3ab - 5bc + 5ac
- ( 2a² - 3c² - 2ab - 3bc + ac )
+ ( -18a² - 5b² - 33ab + 2bc + 12ac)
= ( 1 - 2 - 18 ) a² + ( 2 - 5 )b² + 3c²
+ ( -3 + 2 - 33 ) ab + (-5 + 3 + 2 ) bc
+ ( 5 - 1 + 12 ) ac
= -19a² - 3b² + 3c² - 34ab + 16ac
I hope this helps you.
: )
amun673oyfocs:
yey kya hai bhai.....aur confuse kardiye aap
mere notes me chhota hai bohat ye sum
well thnx......i understood anyhow
we can do it short but it becomes lengthy line.
let it be a lenghty line ones....its BETTER than this method....4 me!!!
That's why I took single term each time .
ohk
Then May I delete the answer
no need answer it once again
nope let it be
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