Question

hey there,
I want to ask a question that: if a=-1 b=-3
find the value of 4a^2-b^2+6a^2-7b^2


please solve it:):):):

Answer 1

Answer:

= -62

Step-by-step explanation:

a = -1 , b = -3

4a^2-b^2+6a^2-7b^2 = ?

$4a^2-b^2+6a^2-7b^2\\=4(-1)^2-(-3)^2+6(-1)^2-7(-3)^2\\=4(1)-(-3\times-3)+6(1)-7(-3\times-3)\\= 4-(9)+6-7(9)\\=10-9-63\\=10-72\\=-62$

Answer 2

Here is a simple solution..Refer that..