✬ HeY There ! ✬
➥ Solve the following equations.
1.} x² + 5x – (a² + a – 6) = 0
2.} x² – (2b – 1)x + (b² – b – 20) = 0
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Answered by
31
Answer:
❶ x² + 5x - (a² + a - 6) = 0
⇒ x² + 5x - (a + 3)(a - 2) = 0
⇒ x² + {(a + 3) - (a - 2)}x - (a + 3)(a - 2) = 0
⇒ x² + (a + 3)x - (a - 2)x - (a + 3)(a - 2) = 0
⇒ x{x + (a + 3)} - (a - 2) {x + (a + 3)} = 0
⇒ {x + (a + 3)} {x - (a - 2)} = 0
⇒ x + (a + 3) = 0 ; x - (a - 2) = 0
⇒ x = - (a + 3) ; x = (a - 2)
➠ x = - (a + 3) , (a - 2)
❷ x² - (2b - 1)x + (b² - b - 20) = 0
⇒ x² - (b - 5)x - (b + 4)x + (b + 4) = 0
⇒ x{x - (b - 5)} - (b + 4) {x - (b - 5)} = 0
⇒ {x - (b - 5)}x - (b + 4) = 0
⇒ x - (b - 5) = 0 ; x - (b + 4) = 0
⇒ x = (b - 5) ; x = b + 4
➠ x = (b - 5) , (b + 4)
Glorious31:
Perfect
Answered by
45
Step-by-step explanation:
1.} x² + 5x – (a² + a – 6) = 0
2.} x² – (2b – 1)x + (b² – b – 20) = 0
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