Question

Hey users


Provide me the answers of Question no.8

Answer 1

(1/sinx-sinx)*(1/cosx-cosx)*(sinx/cosx+cosx/sinx)
=(1-sin²x/sinx)*(1-cos²x/cosx)*(sin²x+cos²x/sinxcosx)
=cos²x/sinx*sin²x/cosx*1/sinx cosx
=1
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Answer 2

$(\frac{1}{ \sin(x)} - \sin(x) ) \times ( \frac{1}{ \cos(x)} - \cos(x) ) \\ \times ( \frac{ \sin(x) }{ \cos(x) } + \frac{ \cos(x) }{ \sin(x) } ) \\ = \frac{1 - { \sin}^{2} (x) }{ \sin(x) } \times \frac{1 - \cos^{2} {(x) } }{ \cos(x) } \times \\ \frac{ \sin^{2}(x) + \cos^{2} (x) }{ \sin(x) \cos(x) } \\ = \frac{ \cos^{2} (x) }{ \sin(x) } \times \frac{ \sin^{2} (x) }{ \cos(x) } \times \frac{1}{ \sin(x) \cos(x) } \\ = \frac{ \sin(x) \cos(x) }{ \sin(x) \cos(x) } \\ = 1$