Question

Hey❤️❤️❤️
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Vapour density of N2O4 is 45.86 at a certain temperature. The degree of dissociation of N204 at the same temperature would be approximately.


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By Choudhary21 ❤️
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Answer 1

Answer:

The relationship between molar mass and vapour density is Molar mass =2× vapour density =2×30=60

N2O4. NO2

Initial moles 

1 0

Moles at equilibrium  

1−α 2α

Mole fraction

( 1−α by (2a by

1+a) 1+a)

Thus 92(1−α by. + 46 ( 2a by. = 60

1+a) 1+a)

α=0.533

The percentage dissociation of N2O4 is 53.3%.

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Answer 2

Answer:

Solution :

<br> molecular mass of

<br> Vapour density,

<br> Let the degree of dissociation be x. <br> Given

<br> applying the relationship, <br>

<br> Degree of dissociation

53.3%