Question

hey ❣️

write formula of


(1/) Sin(A+B)

(2)Cos (A+B)

(3)Cos 2A


​

Answer 1

⏩Hey mate❤

Answer :-

(1) Sin (A+B)

=Sin A cos B +Cos A Sin B

(2) Cos (A+B)

= Cos A CosB - Sin A Sin B

(3) Cos 2A = 2Cos²A -1

or,

= 1-2Sin ² A

or,

= (1-tan²A)/(1+tan²A)

⏩Hopes its help's u

➡@Abhi❤❤

Answer 2

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the formula of .....

1)sin(A+B)

2)cos (A+B)

3)cos 2A

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1)

Sin(A+B)=sinAcosB+cosAsinB

2)

cos(A+B)=cosAcosB-sinAsinB

3)

cos 2A=cos²A-sin²A