Physics, asked by Anonymous, 11 months ago

♡♡♡♡ heya! 25 points______ write a relation between refractive index of denser medium and Critical Angle in case of total internal reflection​

Answers

Answered by Blaezii
9

Heya Dear:❤❤

Your Answer:

Relation between refractive index of denser medium and Critical Angle in case of total internal reflection:-

Total Internal Reflection and the Critical Angle. If a ray of light is leaving a denser medium, it will bend away from the normal. As can be seen from the above diagram, as the angle of incidence inside the material increases the angle of refraction increases to a point at which it leaves the material at 90˚.

When the angle of refraction is equal to 90°, the angle of incidence is called the critical angle, At any angle of incidence greater than the critical angle, the light cannot pass through the surface - it is all reflected. Total because all of the energy is reflected.

Total internal reflection, in physics, complete reflection of a ray of light within a medium such as water or glass from the surrounding surfaces back into the medium. The phenomenon occurs if the angle of incidence is greater than a certain limiting angle, called the critical angle.

 It happens due to a specific process. This process is known as Total Internal Reflection. Case 1: The light bends towards a line called normal. It happens when the light starts from a medium that is rarer and enters to a medium that is denser.

Also, water is an optically denser than air, so when a beam of light enters into air, it bends away from the normal. When a ray of light goes from a rarer medium to a denser medium, its speed decreases or it slows down.

Mathematical Relation:

The relationship between critical angle and refractive index can be mathematically written as –

                                        SinC=1μab

Where,

=>C is the critical angle.

=>μ is the refractive index of the medium.

=>a and b represent two medium in which light ray travels.

Critical angle to Refractive index Formula:

Critical angle to Refractive index : SinC=1μab

Refractive index to Critical angle Formula:

Refractive index to Critical angle : μab=1sinC

"Critical angle and refractive index relation derivation "

The relationship between critical angle and refractive index can be derived as –

Consider a ray of light,

=>Let the angle of incidence i be critical angle C.

=>Let the angle of refraction r=900

=>Refractive index of the rarer medium be μa

=>Refractive index of the denser medium be μb

=================================

Done!

Keep SmilinG!


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Answered by bharat2002
2

Answer:

 \sin(c )  = 1  \div refractive \: index \\

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