Question

HEYA! 30 Points. don't spam or else ur account will be DELETED!!
INSTRUCTION
•The photo that I have given in attachment is from my text book and the given question which I have written is similar to the attached one but the numbers are different. so I want u to answer this question by the attachement answer method.
Rajesh wants to get an inverted image of height 7 cm of an
object kept at a distance of 25 cm. in front of a concave
mirror. The focal length of the mirror is 15 cm. At what
distance from the mirror should he place the screen? What
will be the type of image and what is the height of the object?​

Answer 1

$\huge\underline\mathrm\red{Given}$

hi = -7cm

u = -25cm

f = -15cm

v = ?

ho = ?

$\huge\underline\mathrm\red{Solution}$

Applying mirror Formula

$\implies\sf \frac{1}{v}+\frac{1}{u}=\frac{1}{f}$

$\implies\sf \frac{1}{v}+\frac{-1}{25}=\frac{-1}{15}$

$\implies\sf \frac{1}{v}=\frac{1}{25}-\frac{1}{15}$

$\implies\sf \frac{1}{v}=\frac{3-5}{75}$

$\implies\sf \frac{1}{v}=\frac{-2}{75}$

$\implies\sf v=\frac{-75}{2}=-37.5cm$

Now height of object

$\implies\sf \frac{-v}{u}=\frac{hi}{ho}$

$\implies\sf \frac{-(-37.5)}{-25}=\frac{-7}{ho}$

$\implies\sf -1.5\times{ho}=-7$

$\implies\sf ho=\frac{-7}{-1.5}=+4.6cm$

Nature of image

Nature = real and inverted

Size = Diminished

Position = between centre of curvature and focus

Note :

v = image distance

u = object distance

hi = image height

ho = object height

f = focal length

Answer 2

Answer:

HEYA! 30 Points. don't spam or else ur account will be DELETED!!

INSTRUCTION

•The photo that I have given in attachment is from my text book and the given question which I have written is similar to the attached one but the numbers are different. so I want u to answer this question by the attachement answer method.

Rajesh wants to get an inverted image of height 7 cm of an

object kept at a distance of 25 cm. in front of a concave

mirror. The focal length of the mirror is 15 cm. At what

distance from the mirror should he place the screen? What

will be the type of image and what is the height of the objec