heya.....❤☺️☺️
50 points
no spam
Attachments:
Answers
Answered by
2
2sin5A Cos2A = Sin7A + Sin3A
2sin6AcosA = sin 7A + sin 5A
2SinA Sin2A = CosA- cos 3A
2Cos2A cos 3A =Cos5A + Cos A
Multiply by 2 in N AND D
sin7 A + Sin 3A - sin7A - sin5A)/( cosA- cos 3A - cos5A - cosA)
= sin3A- sin5A)/( cos 3A- cos5A)
= - 2sin Acos 4A )/( -2 cos A cos4A)
= tanA
brainliest pls
Answered by
8
Answer:
2sin5A Cos2A = Sin7A + Sin3A
2sin6AcosA = sin 7A + sin 5A
2SinA Sin2A = CosA- cos 3A
2Cos2A cos 3A -Cos5A + Cos A
Multiply by 2 in N AND D
sin7 A+ Sin 3A-sin7A - sin5A)/(cosA cos 3A - cos5A - cosA)
= sin3A-sin5A)/(cos 3A- cos5A)
= -2sin Acos 4A)/(-2 cos A cos4A)
= tanA
Similar questions