Question

Heya!!

54. A bullet of mass m moving horizontally with velocity v strikes a wooden block of mass M suspended with a string of length l. The bullet gets embedded into the block as a result the block rises up to a height h. find the initial speed of wooden block and the embedded bullet system



Anyone of my friends here??​

Answer 1

Raghvendra 9th

The situation is as shown in the figure.

Let V be velocity of the block-bullet system just after collision. Then by the law of conservation of linear momentum, we get

mv=(m+M)V

V=

m+M

mv

Let the block rises to a height h.

According to law of conservation of mechanical energy,

we get

21 (m+M)V

2=(m+M)gh

h= 2gV 2

= 2gv2 (m+Mm ) 2 .

Answer 2

Hello Dear

• You have to use Conservation of Momentum here,

Let ,

mv = (m+M) V

where V is a velocity of block and bullet combined after hit.

Now, when Block rises up the kinetic energy of block converted into potential energy.

so,

1/2 (m+M) V^2 = (m+M)gh

V^2 = 2gh

V = √2gh

so, we get

v = ( (m+M) ×√2gh) / m

Hope it's helpful!!