heya adarsh answer this also plzzzzz a car moving with a speed of 50 km/hr, can be stopped by brakes after at least 6m...If the same car is moving at a speed of 100 km /hr, the minimum stopping distance is ????
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24 m Mark as brainliest
Explanation:
speed of car, u = 50km/h = 50 × 5/18 = 125/9 m/s
car can be stopped by brakes after at least 6m.
so, stopping distance of car, S = 6m
we know formula of stopping distance = u²/2a, where u is initial speed of car and a is retardation acts on car.
now, 6 = (125/9)²/2a
a = (125/9)²/12 …..(1)
speed of car , U = 100km/h = 100 × 5/18
= 250/9 m/s
so, stopping distance, S' = (250/9)²/2a
= (250/9)²/2{(125/9)²/12}
= 6 × 4 = 24m
stopping distance of 2nd car is 24m
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