Physics, asked by Anonymous, 11 months ago

❇️HEYA❇️

An electric pump is 60 efficient and is rated 2 HP Calculate the maximum amount of water it can lift through a height of 5 min 40 s.
Take g = 10 m/s2 and HP = 750 W]

✔️✔️help please ✔️✔️

Answers

Answered by ritesh275
8

Let the amonit of water be m kg.

Given Comditions-

Power = 2 HP.

= 2 × 750

= 1500 W. As per as the question, electric pump is 60% efficient. Thus, Power of the pump = (60/100) × 1500. = 900 W.

Height = 5 m

Time = 10 seconds.

Acceleration due to gravity = 10 m/s^2

Using the formula,

Work done = mgh

= m × 10 × 5

= 50 × m.

Now, Power = Work/Time

900 = 50 × m/10

m = 180 kg.

Thus, the amount of water is 180 kg.

Answered by Anonymous
6

✴ola!!!!✴

1 HP=750W

So, 2HP = 750 W × 2

2HP = 1500W

Power = (60/100)× 1500 = 900 W

=> Work done by electric pump in lifted height = mgh = m×10s^-2 × 5 = 50 m^2s^-2

=> m×50m^2s^-2 = 900

m= 900/50

=> 180kg answer✔✔

tysm❤

Similar questions