Question

heya...
answer my question plss!!!​

Answer 1

Step-by-step explanation:

ʟᴇᴛ x ɪs ᴛʜᴇ ᴅɪɢɪᴛ ᴏɴ ᴏɴᴇs ᴘʟᴀᴄᴇ ᴛʜᴇɴ 3x ᴡɪʟʟ ʙᴇ ᴏɴ ᴛᴇɴs ᴘʟᴀᴄᴇ.

sᴏ ɴᴜᴍʙᴇʀ ɪs 10*3x+x=31x

ɴᴏᴡ ɪғ ᴡᴇ ʀᴇᴠᴇʀsᴇ ᴛʜᴇ ᴘᴏsɪᴛɪᴏɴ ᴏғ ᴅɪɢɪᴛ

ᴛʜᴇɴ ɴᴇᴡ ɴᴜᴍʙᴇʀ ɪs

10*x+3x=13x

ɴᴏᴡ,18x=36

ᴛʜɪs ɪᴍᴘʟɪᴇs x=2

sᴏ ᴛʜᴇ ɴᴜᴍʙᴇʀ ɪs 10*3*2+2=62

ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs

Answer 2

Let the two digit number be $\sf{10x+y.}$ Here $\sf{x}$ is the tens digit and $\sf{y}$ is the ones digit.

Given that the tens digit is three times the ones digit. Then we have,

$\longrightarrow\sf{x=3y}$

So our two digit number in terms of $\sf{y}$ will be,

$\longrightarrow\sf{10x+y=10(3y)+y}$

$\longrightarrow\sf{10x+y=31y}$

The number formed by reversing the digits is $\sf{10y+x,}$ which in terms of $\sf{y}$ will be,

$\longrightarrow\sf{10y+x=10y+3y}$

$\longrightarrow\sf{10y+x=13y}$

Given that our two digit number is 36 greater than the number formed by reversing the digits. Then,

$\longrightarrow\sf{31y=13y+36}$

$\longrightarrow\sf{18y=36}$

$\longrightarrow\sf{y=2}$

Then,

$\longrightarrow\sf{x=3y}$

$\longrightarrow\sf{x=3\times2}$

$\longrightarrow\sf{x=6}$

Hence our two digit number is,

$\longrightarrow\sf{10x+y=10\times6+2}$

$\longrightarrow\sf{\underline{\underline{10x+y=62}}}$