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V = 1 m^3 = 1000 L
P= 1 atm
T = 27 C = 300 k
n= PV/RT
= 1× 1000/ 0.082 × 300
= 10^4/ 246
1 mole contains 6.023× 10^23 molecules
So 10^4 /246 contains 6.023× 10^23 × 10^4/246
= 6.023 × 10^27/ 246
= 0.0244 × 10^27
= 2.44 × 10^25 molecules
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