Math, asked by DevilDoll12, 1 year ago

Heya!! Answer this trigonometry Question [ Class 11 ] ⬇⬇

➡Find the Value of Sin ( - 1125° ) .

⏪Answer with Proper Explanation ⏩
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siddhartharao77: Dont disturb others!

Answers

Answered by siddhartharao77
15

Given sin(-1125)

(1)

Sin(1125)

= > sin(360 * 3 + (1/4) * 180)

= > sin((1/4) * 180))

= > sin(45)

Now,

Sin(-1125) = sin(-45)

 = > Answer : \boxed{-\frac{1}{\sqrt{2}}}

Or

On rationalizing, we get

 = > \frac{-1}{\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}}

 = > \frac{-\sqrt{2}}{\sqrt{2} * \sqrt{2}}

 Answer : \boxed{\frac{-\sqrt{2}}{2}  }

Hope this helps!


DevilDoll12: :-)
DevilDoll12: Thanks ☺
siddhartharao77: Welcome
DevilDoll12: But isn't Sin45°= 1/√2
siddhartharao77: on rationalizing 1/root. it will become 1/root 2 * root2/root2 = > root2/(root2 * root2) = > root2/2
FuturePoet: ok
DevilDoll12: Ok!! Got it Sir 〰
siddhartharao77: Thanks!
Answered by FuturePoet
14

--Yeah sure for your help

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Here is your answer which you are searching for

=> We know that the value of

----> sin ( - 1125 °) = -1 / root 2

-----> Cosec ( 390 °) = 2/1

-----> Cot ( 570 °) = root 3

Read more on Brainly.in - https://brainly.in/question/4913638#readmore

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Be Brainly

Warm Regards

@ Brainlestuser


FuturePoet: Hope it helps !
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