Question

HEYA






ARRANGE THE FOLLOWING RATIOS IN ASCENDING ORDER OF MAGNITUDE

NO SPAMM


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Answer 1

$( \: 2 \: : \: 3 \:) \: < \: ( \: 5 \: : \: 9 \:) \: < \: ( \: 11 \:: \: 15 \: )$

Step — by — step explanation :-

$2 \: : \: 3 \: \:\: , \: 5 \: : \: 9 \: \: and \: \: 11 \:: \: 15 \:$

$\frac{2}{3}$ , $\frac{5}{9}$ and $\frac{11}{15}$

Lowest Common Multiple of 3 , 9 and 15 is 45

$\frac{2}{3}$ => $\frac{2 × 15}{3 × 15}$ = $\frac{30}{45}$

$\frac{5}{9}$ => $\frac{</em></strong><strong><em>5</em></strong><strong><em> × </em></strong><strong><em>5</em></strong><strong><em>}{</em></strong><strong><em>9</em></strong><strong><em> × </em></strong><strong><em>5</em></strong><strong><em>}$ = $\frac{</em></strong><strong><em>2</em></strong><strong><em>0</em></strong><strong><em>}{45}$

$\frac{11}{15}$ => $\frac{</em></strong><strong><em>1</em></strong><strong><em>1</em></strong><strong><em> × </em></strong><strong><em>3</em></strong><strong><em>}{</em></strong><strong><em>1</em></strong><strong><em>5</em></strong><strong><em> × </em></strong><strong><em>3</em></strong><strong><em>}$ = $\frac{</em></strong><strong><em>3</em></strong><strong><em>3</em></strong><strong><em>}{45}$

So ,

$\frac{30}{45}$ , $\frac{20}{45}$ and $\frac{33}{45}$

Answer 2

$\huge\mathrm{Answer}$

Refer to the above attachment