Question

heya brainliacs please prove cyclic rhombus is square

Answer 1

given:- rhombus ABCD is inscribed in circle.
to prove:- ABCD is a square.
in ∆ ABD and ∆ CBD
BD = BD common
AD = BC opp side of rhombus
AB = DC opp side of rhombus
∆ ABD =~ ∆CBD by SSS
2a+2b=180°( opp side of cyclic quadrilateral are always supplementary)
2(a+b)=180°
a+b=180°/2
a+b=90°
in ∆ ABD
Angle A = 180°-(a+b)
angle A= 180°-90°
angle A= 90°
so, rhombus ABCD becomes a square.

Answer 2

Answer:

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