Question

heya brainlians!
HELP PLEASE
QUESTION:-
if cosec theta+sin theta =4, find the value of (sin²theta+cosec²theta)

please help ASAP​

Answer 1

Answer:

$cosec \: \alpha + sin \: \alpha = 4 \\ \\ = > (cosec \: \alpha + sin \: \alpha ) ^{2} = ({4})^{2} \\ \\ = > {cosec}^ {2} \: \alpha + {sin}^{2} \: \alpha + 2 \times sin \: \alpha \times cosec \: \alpha = 16 \\ \\ = > cosec {}^{2} \: \alpha + {sin}^{2} \alpha + 2 \times 1 = 16 \\ \\ = > {cosec}^{2} \: \alpha + {sin}^{2} \alpha \: + 2 = 16 \\ \\ = > {cosec}^{2} \alpha + {sin}^{2} \: \alpha = 16 - 2 \\ \\ = > {cosec}^{2} \: \alpha + {sin}^{2} \: \alpha = 14 \\ \\ \\ formula \: \: - \: \: (x + y) {}^{2} = {x}^{2} + {y}^{2} + 2 . x.y \\ \\ cosec \: \alpha = \frac{1}{sin \: \alpha }$

Answer 2

Answer:

heya!

here is ur answer in the attachment ✨

hope it's helpful to you

thnku !!!

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