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Let the function f: R – (4/3)→ R – (4/3) is defined by f(x) = (4x+3)/(3x+4). Prove that the given function is bijective. And, find the inverse of the function and f-1(0) and the value of x, such that f-1(x) = 2.
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It is given that f : R → R given by f (x) = 4x + 3
Let x,y ∈ R such that f(x) = f(y)
⇒ 4x +3 = 4y +3
⇒ 4x = 4y
⇒ x = y
therefore, f is one- one function.
Now, for y ∈ R, Let y = 4x +3
∈ R
⇒ for any y ∈ R, there exists x = ∈ R
such that, f(x) =
⇒ F is onto function.
Since, f is one –one and onto
therefore , f is inversible.
now, f(x) = 4x + 3
f(x) = y = 4x + 3
y = 4x + 3
=> y - 3 = 4x
=> 4x = (y - 3)
=> x = (y - 3)/4
=> f(y) = (y - 3)/4
here f(y) is not other than inverse of f(x)
put x in place of y and write f(y) = f⁻¹(x)
e.g., f⁻¹(x) = (x -3)/4
hence, inverse of f(x) = (x-3)/4
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