Question

Heya(^^)

calculate the number of molecules present in 350 cm^3 of NH3 gas at 273K and 2 atmospheric pressure.

dony spamm:-⚠⚠⚠⚠

Answer 1

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pv=nRT

$2×0.35=n×8.314×273 \\ \\ n = \frac{2 \times 0.35}{8.314 \times 273} \\ \\ n = 0.0003$