Question

Heya✨

Can someone please explain this⏫ Asap❗​

Answer 1

AnswEr:-

For any electron moving in $K^th$ circular orbit of radius$r_k$ ,

➩ 2π$r_k$=kλ

Where, λ = h/p

h = plank's constant

p= electron's momentum

Hence,

➩ λ = h/m$v_k$

Therefore,

⇒ 2π$r_k$=kh/m$v_k$

⇒$\sf \bold mv_k r_k =kh/2π.$

Now, as we know :

➩  mvr = nh/2π....(1)

And,

➩ mv = h/v .....(2)

From (1) & (2) :

⇒ 2πr =n(h/mv)

⇒ 2πr = nλ

2πr represents circumference here.

Hence proved !

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Answer 2

Refer to the attachment ⬆️⬆️