Question

heya ! cuteees!....solve it out....got .stucked in the middle​

Answer 1

Heya!!

Here's ur solution!!

Step-by-step explanation:

Square and add for x² + y² = a² + b²

so, y² = (a² + b²) - x²

$= 2y (\frac{dy}{dx} ) \: = - 2 \: = > \frac{dy}{dx} = \frac{ - x}{y} </em></p><p></p><p></p><p><em>\\</em></p><p></p><p><em> = \frac{ {d}^{2}y }{d {x}^{2} } = \frac{ - 1}{y} + \frac{x (\frac{dy}{dx}) }{ {x}^{2} } </em></p><p></p><p><em>\\ = > {y}^{2} ( \frac{ {d}^{2}y }{d {x}^{2} }) \: - x( \frac{dy}{dx} ) + y = 0$

Glad help you

thank you ☺