Question

Heya!

Differentiate
1)sin(3x + 5)

Please don't spam :)​

Answer 1

Answer:

See to my attachment

Hope it will help you bro✌.

Answer 2

Question :

Differentiate

1)sin(3x + 5)

Solution :

$\displaystyle y = \sin(3x + 5)$

Differentiating with respect to x we get ,

$\implies{ \displaystyle \frac{dy}{dx} = \frac{d\{ \sin(3x + 5) \}}{dx} }$

By using chain - rule ,

$\implies{\displaystyle \frac{dy}{dx} = \frac{d\{ \sin(3x + 5) \}}{d(3x + 5)} \times \frac{d (3x + 5)}{dx} }$

$\implies{\displaystyle \frac{dy}{dx} = \cos(3x + 5) \times 3}$

$\boxed{ \red{\displaystyle \frac{dy}{dx} = 3\cos(3x + 5)}}$