Heya,
Factorise,
a^3 (b - c) + b^3 ( c - a) + c^3 ( a - b)
Need accurate answer!! :)
Answers
Answered by
3
ello
plz refer the given attachment
thanks a lot anku di
plz refer the given attachment
thanks a lot anku di
Attachments:
ANSHI03:
Hehe... Dont say thanks...
Answered by
3
Given Equation is a^3(b - c) + b^3(c - a) + c^3(a - b).
Now,
This equation can be written as :
(a(b-c))^3 + (b(c-a))^3 + (c(a - b))^3.
Now,
a + b + c = a(b-c) + b(c-a) + c(a - b)
= ab - ac + bc - ba + ca - cb
= 0.
We know that when a + b + c = 0 then a^3 + b^3 + c^3 = 3abc.
Therefore,
(a(b - c))^3 + (b(c - a))^3 + (c(a - b))^3 = 3(a(b - c))(b(c-a))(c(a-b))
= 3abc(b-c)(c-a)(a-b).
Hope this helps!
Now,
This equation can be written as :
(a(b-c))^3 + (b(c-a))^3 + (c(a - b))^3.
Now,
a + b + c = a(b-c) + b(c-a) + c(a - b)
= ab - ac + bc - ba + ca - cb
= 0.
We know that when a + b + c = 0 then a^3 + b^3 + c^3 = 3abc.
Therefore,
(a(b - c))^3 + (b(c - a))^3 + (c(a - b))^3 = 3(a(b - c))(b(c-a))(c(a-b))
= 3abc(b-c)(c-a)(a-b).
Hope this helps!
Similar questions