Question

Heya friends...Please help me to solve this quadratic equation:

√4x-3+√2x+3=6


Ans: 3

(❌Don't copy it from anywhere❌)​

Answer 1

Heya!

Here is ur answer...

√4x-3+√2x+3 = 6

√4x-3 = 6-√2x+3

By squaring on both sides

(√4x-3)^2 = (6-√2x+3)^2

4x-3 = 36 + 2x+3 -12√2x+3

4x-3 = 39+2x-12√2x+3

12√2x+3 = -4x +2x +3+39

12√2x+3 = -2x +42

By squaring on both sides

(12√2x+3)^2 = (-2x +42)^2

432 +288x = 4x^2 +1764 -168x

4x^2 -168x -288x +1764 -432 = 0

4x^2 - 456x + 1332 = 0

x^2 -114x + 333 = 0

Now factorise it!

x^2 -114x +333 = 0

x^2 -111x -3x +333 = 0

x(x-111) -3(x-111) = 0

(x-111)(x-3) = 0

x = 111 or x = 3

Hope it helps u..

Answer 2

hope it helps!

mark as brainliest!