Heya friends...Please help me to solve this quadratic equation:
√4x-3+√2x+3=6
Ans: 3
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Answers
Answered by
1
Heya!
Here is ur answer...
√4x-3+√2x+3 = 6
√4x-3 = 6-√2x+3
By squaring on both sides
(√4x-3)^2 = (6-√2x+3)^2
4x-3 = 36 + 2x+3 -12√2x+3
4x-3 = 39+2x-12√2x+3
12√2x+3 = -4x +2x +3+39
12√2x+3 = -2x +42
By squaring on both sides
(12√2x+3)^2 = (-2x +42)^2
432 +288x = 4x^2 +1764 -168x
4x^2 -168x -288x +1764 -432 = 0
4x^2 - 456x + 1332 = 0
x^2 -114x + 333 = 0
Now factorise it!
x^2 -114x +333 = 0
x^2 -111x -3x +333 = 0
x(x-111) -3(x-111) = 0
(x-111)(x-3) = 0
x = 111 or x = 3
Hope it helps u..
Answered by
1
hope it helps!
mark as brainliest!
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